Working in real euclidean space:
Let A \subseteq \mathbb R^n
A point is always one of the 1., 2., or 4., and always only one of them.
Let A \subseteq \mathbb R^n
A point p \in \mathbb R^n is a limit point of a sequence \{x_i\}_{i=1}^\infty if every neighborhood of p contains an infinite number of x_i.
If p is a limit point of a set A \subseteq \mathbb R^n then there exists a sequence of points \{x_i\}_{i=1}^\infty where x_i \in A such that p is a limit point of the sequence.
If \{x_i\}_{i=1}^\infty is a sequence with each x_i \in A and p is a limit point of the sequence then p is a limit point of A.
A neighborhood of a point x \in A relative to A is a set of the form D^n(x, r) \cap A.
Let B \subseteq A. The set B is open relative to A if every x \in B is an interior point relative to A.
Let B \subseteq A \subseteq \mathbb R^n:
Let D \subseteq \mathbb R^n and R \subseteq \mathbb R^m.
A function f: X \to Y is a homeomorphism if f is continuous and f^{-1} is continuous. The spaces X and Y are called topologically equivalent (homeomorphic).
P is a topological property if whenever set A has property P and set B is topologically equivalent to A, then B has property P.
A subset A of \mathbb R^n is compact if every sequence of points in A has a convergent subsequence to a point in A.
Let A \subseteq \mathbb R^n be a compact subset, and let f: A \to \mathbb R^m be a continuous map. Then f(A) is a compact set.
A subset A of \mathbb R^n is compact iff it is closed and bounded.
A set S is connected if whenever S is divided into two nonempty disjoint sets, one contains a limit point of the other.
The set S is connected iff S cannot be written as a union of two nonempty disjoint sets which are open relative to S.
If f: D \to R is a continuous function from a connected set D onto a set R, then R is connected.
[0; 1] is compact and connected.
If f: X \to X a point x_0 \in X such that f(x_0) = x_0 is called a fixed point of f
If f: [0; 1] \to [0; 1] is a continuous function, then there is a fixed point of f, ie a point x_0 \in [0; 1] such that f(x_0) = x_0
A space X has the fixed point property if every continuous map f: X \to X has a fixed point.
The fixed point property is a topological property.
The points on an n-sphere x = (x_1, \cdots, x_n) and -x = (-x_1, \cdots, -x_n) are called antipodal.
If f: S^1 \to \mathbb R is continuous, then there exists an x_0 \in S^1 such that f(x_0) = f(-x_0).
At any one point there are two diametrically opposite points with the same temperature.
Let A, B be bounded connected open subsets in \mathbb R^2 which may overlap. There exists a line which divides each region in half.